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Use the References to access important values if needed for this question. 1. What is the mass of $1.72 \times 10^{24}$ atoms of cesium? 2. How many cesium atoms are there in 28.4 grams of cesium?

          Use the References to access important values if needed for this question.
1. What is the mass of $1.72 \times 10^{24}$ atoms of cesium?
2. How many cesium atoms are there in 28.4 grams of cesium?
        
Use the References to access important values if needed for this question.
1. What is the mass of 1.72 × 10^24 atoms of cesium?
2. How many cesium atoms are there in 28.4 grams of cesium?

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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[Reviem Topics]] [References] Use the References to access important values if needed for this question. What is the mass of 1.72 imes 10^(24) atoms of cesium? grams How many cesium atoms are there in 28.4 grams of cesium? atoms 7 more group attempts remaining ticles [Review Topics] [References] Use the References to access important values if needed for this question 1.What is the mass of 1.72x1024 atoms of cesium? grams 2.How many cesium atoms are there in 28.4 grams of cesium? atoms Submit Answer Retry Entire Group 7more group attempts remaining
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Transcript

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00:01 In this video, we are going to focus on finding out the complete atomic symbol for cesium.
00:05 So here we can firstly write a part and in the a part we can say that the given value is here basically 132 .90545519 and then here we have four zeros.
00:22 Right? so this can be approximately written as 133 and thus we we can say that the symbol for cesium can be written as it will be here 133 and then here it will be 55.
00:40 So we must understand that here we write the atomic symbol and here we write the mass number.
00:47 So it will be here mass and then it is basically number and now here we have written atomic number.
00:57 So this very symbol can also be written as we can say it is here equals to this will be same right.
01:05 So it is cesium and then here we can write 55 and then here we can write 133.
01:11 So these two format we follow to answer such kind of problems.
01:15 So this will be our answer for the first part of this very problem.
01:18 Now let us see how we can answer the second part of this very question.
01:23 And in the second part let us here write that we are.
01:27 Are basically having the values of proton.
01:31 So how many protons are there in cesium? so number of protons in cesium is basically 55.
01:38 And then number of neutrons in cesium can be written as it will be equals to 78.
01:45 So now here we can say that the number of electrons is here going to be equals to 55.
01:53 So if we denote this number of protons with p and then, then this number of neutrons with n and this number of electrons with e, then we can here write that atomic mass of cesium will be here equals to atomic and then here we are having mass and now it will be cesium.
02:12 So this very value is going to be here equals to 55 multiplied with mass of proton which can be denoted as such and then it will be here plus 78 multiplied with mass of neutrons.
02:27 Now here we can say that at last we are going to have 55 times mass of electrons...
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