00:01
Hi, in the first part, that is part a of this question, we have to calculate the average kinetic energy of a gas molecule at temperature t given as 21 degree celsius.
00:13
Now, average kinetic energy is calculated using formula 3 by 2 kbt.
00:23
So we can write this as 3 by 2 into kb, which is a constant 1 .38 into 10 raised 2 power.
00:32
Minus 23 jule per kelvin into 21 plus 273 kelvin as it was in degree celsius.
00:44
So on solving this, we get the value of kinetic energy average equals to 6 .08 into 10 raised to power minus 21 june.
00:56
Now moving on to the next part, part b, in which we have to calculate the internal energy of a gas of 3 .2 moles.
01:05
So, n is 3 .2 at same temperature, that is t equals to 21 degree celsius.
01:13
Now, internal energy, u is equals to 3 by 2 nrt.
01:20
So this will be equals to 3 by 2 into 3 .2 into 8 .314 into 294, which is 21 degree celsius kelvin.
01:37
So we get the value of u equals to 117 .2 .7 jule.
01:44
Now moving on to the third part, part c of this question in which we have a monoatomic ideal gas having volume v given as 0 .0030 meter cube and pressure p is given as 7 into 10 raise 2 power 5 pascal.
02:02
So we have to calculate its internal energy.
02:06
So internal energy will be equals to 3 by 2 pv where p is pressure and v is volume.
02:16
So we have both...