00:01
Hello students, to express the given rational expression with the common denominator 4c -1, c -2, c plus 3, we need to factor the denominator of the original expression to find the missing terms in the numerator.
00:15
So the first one is given as 1 by 4c square minus 9c plus 2 and the second one is given as 9c by 4c square plus 11c minus 3.
00:30
So now let's factor the denominator.
00:34
So for the first one the denominator is 4c square minus 9c plus 2.
00:39
We can rewrite it as 4c square minus 8c minus c plus 2.
00:46
So this is equal to taking 4c as common so we have c -2 and here we are taking minus 1 as common so we will have c -2.
00:54
So, 4c minus 1, c minus 2 and the second one now, 4c square plus 11c minus 3.
01:05
So we can rewrite it 4c square plus 12c minus c minus 3.
01:12
So taking 4c as common we have c plus 3, minus 1 as common c plus 3...