00:01
Hi, from the question given that consider the polynomial p of x is equal to x to the power of 4 minus 81.
00:11
So, here we need to find the product of linear factor and zeros of the polynomial.
00:17
So, product of the linear factor that is p of x can be written as x squared the whole square minus 9 squared and in general we know that a squared minus b squared is equal to a plus b times a minus b.
00:37
So, here the product of the polynomial will be p of x is equal to x squared minus 9 times x squared plus 9.
00:51
So, again this term can be written as x squared minus 3 squared times x squared plus 9.
01:00
So, again use the same formula.
01:03
So, we obtain x plus 3 times of x minus 3 times x squared plus 9.
01:11
So, the product of the linear factor will be x plus 3 times of x minus 3 times x squared plus 9 and the zeros of the polynomial will be p of x is equal to 0.
01:29
So, x plus 3 times of x minus 3 times of x squared plus 9 will be equal to 0.
01:39
So, here x is equal to minus 3 and plus 3 and x squared is equal to minus 9...