00:01
Hello students in the question.
00:02
We are given three charges electric field due to negative charge it acts towards the charge.
00:09
We have electric field due to positive charges.
00:12
It is away from the charges here electric field due to this charge.
00:18
It would be in this direction in electric field with this charge would be in this direction.
00:24
We would get net electric field at point p.
00:30
It is equal to erp plus esp plus etp electric field.
00:43
It is given by formula k constant into charge q divided by r square.
00:50
Here r is distance.
00:52
We can write erp it is equal to k times minus q divided by distance square that is 2a square dot r cap r cap.
01:09
It is unit vector here.
01:12
We have this equal to k q upon 2a square minus r cap.
01:21
We have minus r cap equal to minus radius vector r divided by magnitude of r.
01:28
This is equal to minus a i cap plus a j cap divided by magnitude that is under root 2a.
01:40
This comes out to be equal to minus i cap upon under root 2 minus j cap upon under root 2.
01:48
So we can write similarly we have esp it is equal to k times charge q divided by distance square that is a square r cap.
02:05
Here r cap it is equal to radius vector r divided by magnitude is equal to a j cap divided by a that is j cap.
02:18
Here we can write esp it is equal to k times q divided by a square j cap.
02:30
We have pep it is equal to k times charge q divided by distance square that is 2a square r cap...