Question

Rigid bar BFCD is pinned at C and supported by steel bar AB at B and aluminum bar DE at D. A concentrated load P is applied to the rigid bar at F. Compute the Load P when the downward deflection at F (?=0.6 mm.) 3m A P DE aluminum bar A=900 mm² D E E= 70 GPa 1.5m B FV Rigid bar C ?=0.6 mm 3m AB steel bar A= 650 mm² E= 200 GPa 

          Rigid bar BFCD is pinned at C and supported by steel bar AB at B and aluminum bar DE at D. A concentrated load P is applied to the rigid bar at F. Compute the Load P when the downward deflection at F (?=0.6 mm.)
3m
A
P
DE aluminum bar
A=900 mm²
D
E
E= 70 GPa
1.5m
B
FV Rigid bar
C
?=0.6 mm
3m
AB steel bar
A= 650 mm²
E= 200 GPa
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Rigid bar BFCD is pinned at C and supported by steel bar AB at B and aluminum bar DE at D. A concentrated load P is applied to the rigid bar at F. Compute the Load P when the downward deflection at F (?=0.6 mm.) 3m A P DE aluminum bar A=900 mm² D E E= 70 GPa 1.5m B FV Rigid bar C ?=0.6 mm 3m AB steel bar A= 650 mm² E= 200 GPa

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Rigid bar BFCD is pinned at C and supported by steel bar AB at B and aluminum bar DE at D. A concentrated load P is applied to the rigid bar at F. Compute the Load P when the downward deflection at F = 0.6 mm. The aluminum bar DE has a cross-sectional area A = 900 mm^2 and a modulus of elasticity E = 70 GPa. The steel bar AB has a cross-sectional area A = 650 mm^2 and a modulus of elasticity E = 200 GPa.
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Transcript

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00:01 Hi, let's see balancing vertical force p equal to r aluminum plus r steel.
00:08 So, here r aluminum plus r steel equal to 50000 n.
00:19 Let's take this as equation 1 and r steel equal to 29166 .67 n.
00:27 Let's take this as equation 2.
00:30 Using equation 1 and 2, we have r aluminum equal to 20833 .33 n.
00:38 Let's take this as equation 3.
00:40 Now, delta l aluminum equal to r aluminum into l aluminum divided by a aluminum into e aluminum.
00:54 Let's substitute the value.
00:56 So, we have 20833 .33 into 3 divided by 500 into 10 to the power minus 6 into 70 into 10 to the power 9...
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