00:01
So, here in this question we are given a resistor whose resistance is equals to 10 ohm which is connected in series with a inductor with inductance of 15 henry.
00:11
So, the rl combination is connected to a variable voltage power supply where v is given that is equals to 4 .5 volt by the series as shown here.
00:21
So, here in the first part of the question we have to find out the value of the time constant which is represented by tau of the combination of in the second.
00:31
So, here as we know that tau is equals to l which is divided by r.
00:35
So, we are having the value of the l and r both.
00:38
So, using the term here.
00:40
So, tau is equals to l inductance is given to us that is equals to 15 it is in milli henry.
00:46
So, we can convert this into henry that is equals to 15 multiplied by 10 raise to the power minus 3 henry.
00:52
So, tau from here is equals to 15 multiplied by the 10 raise to the power minus 3 which is divided by r that is equals to 10.
01:00
So, solving the term from here we get the value of tau that become equals to 1 .5 multiplied by the 10 raise to the power minus 3 s...