Question

R = R_o (1 + \alpha \Delta T); \Delta T = T_f - T_i 1) A household stove has a heating element that is made of tungsten wire. The temperature coefficient of resistivity is \alpha = 4.5 \times 10^{-3} / ^\circ C and the supply voltage is 120 V. When the stove is first turned ON the current is found to be 4.0 A and the initial temperature of the wire is 38 $^\circ$C. After heating for a short while the current is found to be reduced. Knowing that the temperature of the wire depends upon the resistance calculate the temperature of the wire when the current is 1.5 A R = 120 / 1.5

          R = R_o (1 + \alpha \Delta T); \Delta T = T_f - T_i
1)
A household stove has a heating element that is made of tungsten wire. The temperature coefficient of resistivity is \alpha = 4.5 \times 10^{-3} / ^\circ C and the supply voltage is 120 V. When the stove is first turned ON the current is found to be 4.0 A and the initial temperature of the wire is 38 $^\circ$C. After heating for a short while the current is found to be reduced. Knowing that the temperature of the wire depends upon the resistance calculate the temperature of the wire when the current is 1.5 A
R = 120 / 1.5

R = Ro (1 + αΔT); ΔT = Tf - Ti
1)
A household stove has a heating element that is made of tungsten wire. The temperature coefficient of resistivity is α= 4.5 ×10^-3 / ^∘C and the supply voltage is 120 V. When the stove is first turned ON the current is found to be 4.0 A and the initial temperature of the wire is 38 ^∘C. After heating for a short while the current is found to be reduced. Knowing that the temperature of the wire depends upon the resistance calculate the temperature of the wire when the current is 1.5 A
R = 120 / 1.5

Added by Erica M.

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