Run a regression analysis on the following bivariate set of data with y as the response variable. xy51.5-3.952.214.822.234.228.456.543.74519.11042671.915.858.826.152.71.596.937.556.8 Verify that the correlation is significant at an α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 91.7 on the response variable. What is the predicted explanatory value?
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To perform a regression analysis on the given bivariate data and verify the significance of the correlation, we will follow these steps: Show more…
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Run a regression analysis on the following bivariate set of data with y as the response variable. x y 91.2 16.5 69.4 39.4 63.8 37.2 58.8 43.9 55.2 31.4 84.6 18.2 57.4 37.9 64.8 33.8 58.3 35.2 68.3 37.5 81.1 26.8 78.1 24.6 68.1 23.5 70.4 34.5 59.2 36.6 Verify that the correlation is significant at an α=0.05α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 23.8 on the response variable.What is the predicted explanatory value?x = (Report answer accurate to one decimal place.)
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Run a regression analysis on the following bivariate set of data with y as the response variable. x y 37.5 67.2 65.9 26.9 41.0 73.8 48.9 68.6 50.0 57.6 63.0 37.9 50.7 57.7 41.7 61.6 78.0 28.6 55.5 35.8 59.2 59.4 Verify that the correlation is significant at an α = 0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 55.2 on the response variable. What is the predicted explanatory value? x = (Report answer accurate to one decimal place.) You run a regression analysis on a bivariate set of data (n = 53). You obtain the regression equation y = -2.585x - 16.627 with a correlation coefficient of r = -0.475 (which is significant at α = 0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 180 on the response variable. What is the predicted explanatory value? x = (Report answer accurate to one decimal place.)
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