Question 5 Solve \frac{x^2 + 8x + 16}{x + 4} = \frac{-1}{x + 2} A. \quad x = -3 B. \quad x = 3, -2 C. \quad x = 3 D. \quad x = -3, 2

          Question 5
Solve \frac{x^2 + 8x + 16}{x + 4} = \frac{-1}{x + 2}
A. \quad x = -3
B. \quad x = 3, -2
C. \quad x = 3
D. \quad x = -3, 2

Added by Joel T.

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

09/23/2022

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Step 1: Rewrite the equation as (x^2 + 8x + 16)/(x + 4) = -1/(x + 2) Show more…

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s (D) (4y)/(xy)=(4)/(y) Question 5 Solve (x^(2)+8x+16)/(x+4)=(-1)/(x+2) x=-3 x=3,-2 x=3 x=-3,2 20 Question 5 x+8x+16 Solve x+4 -1 r+2 B x=3,-2 -3,2

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