Question

Given: $G(s) = \frac{s+1}{(s-3)(s+2)}$ a.) Design $G_c(s)$ using Pole Placement to Make CLS to settle around 1 sec w/o oscillation b.) Can you modify the block diagram to achieve zero SSE for Constant $r(t)$ signal

          Given: $G(s) = \frac{s+1}{(s-3)(s+2)}$

a.) Design $G_c(s)$ using Pole Placement to Make CLS
to settle around 1 sec w/o oscillation

b.) Can you modify the block diagram to achieve
zero SSE for Constant $r(t)$ signal
        
Given: G(s) = (s+1)/((s-3)(s+2))

a.) Design Gc(s) using Pole Placement to Make CLS
to settle around 1 sec w/o oscillation

b.) Can you modify the block diagram to achieve
zero SSE for Constant r(t) signal

Added by Kevin W.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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S+1 (ivC:Gls=Zs-3(s+2) YcS a.) Design Gc(s) using Po1c Placener to Make CLS 6-(S) to Settle cVOUnd 1 Sec W/o Oscillation b.) (c You Modify the block diagram to achieve ZCSo SSE for Long-term Signal
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00:01 In this question the given block diagram is as this block diagram reduction g2 g3 are connected in parallel and there are cascaded with g1 and these are cascaded g1 the resultant is therefore g2 plus gs into g1 which can be shown as the below diagram now shift the summing point…
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