S2o32 2cl2 6 oh 4cl 2so32 3 h2o for the above redox reaction...

S2O3^2- + 2Cl2 + 6OH- -> 4Cl- + 2SO3^2- + 3H2O For the above redox reaction, assign oxidation numbers and use them to identify the element oxidized and the element reduced. Name of the element oxidized: fill in the blank 1 Name of the element reduced: fill in the blank 2 5N2 + 2Br2 + 8H2O + 4OH- -> 4BrO3- + 5N2H4 For the above redox reaction, assign oxidation numbers and use them to identify the element oxidized and the element reduced. Name of the element oxidized: fill in the blank 1 Name of the element reduced: fill in the blank 2

Transcript

00:01 Hi, in this question we have given this equation we need to find out oxidation number and identification of oxidized and reduced element we can see s2 03 2 minus is not reducing or oxidizing as it remains same even after the reaction so there will be no oxidation number change in case of cl 2 we can see the change is cl minus so in cl 2 the oxidation number is 0 and in cl minus the oxidation number is minus the oxidation number is minus 1 so in reactant form it is 0 and in product form it is minus 1 in oh h minus the oxidation number is minus 1 and in h2.

00:40 The oxidation number for o will be minus 2 and for h it would be plus 1 and here in oh h minus we will not consider o and h differently because o h minus is a species and for h 2 o if we consider it as a one species then the oxidation number will be 0.

01:05 So oxidation number or on for cl 2 is 0 for cl minus it is minus 1 for oh minus this is minus 1 for h2o this is 0.

01:24 Now cl 2 is changing to cl minus from 0 to minus 1.

01:34 So this is reduction.

01:40 And this is reduced species on the other hand oh h minus is forming h2o so the oxidation number changes minus 1 to 0 so this is oxidation these will be oxidized species the next is same here in n2 the oxidation number is 0 for b r 2 this is also 0 for h2 this is 0 for h2 this is 0 oh, h minus the oxidation number is minus 1 in bro3, br is bro3 minus.

02:38 So br is in plus 7 and oxygen is in minus 2.

02:47 Also for n2h4, nitrogen is in minus 2.

02:54 So the change for nitrogen is 0 to minus 2 and for br the change is 0 to plus 7 and for h2o the change is 0 to minus 1...

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