59. Use the data and results from Problem 1. Besides, design for a reliability of 0.90 and a design life of 2000 h. The uncertainty of the actual use of the tractor calls for a service (safety) factor of 1.25.
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The design life is given as 2000 hours. Since the safety factor is 1.25, we need to divide the design life by the safety factor to get the actual life of the tractor. Actual life = Design life / Safety factor Actual life = 2000 hours / 1.25 Actual life = 1600 Show more…
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