00:01
Hello reven, let's look at the question.
00:04
Now in this question, so we have to find out the molecular formula of cellic acid and the two reactions of cellic acid are given and the amounts of the products involved as well as the reactant involved is also given.
00:22
From that we have to find out the molecular formula of cellic acid.
00:27
Okay.
00:28
Now see here.
00:30
First, let us find out.
00:31
The molar mass of cellic acid which can be found out by using titration values so first let me take titration values and first let me find out its molecular formula sorry molecular mass after that we can find out the molecular formula okay now here it is given that the mass of cellcillic acid taken is mass of salicylic acid is equal to so 1 gram and the concentration of naoh is nahoh is equal to 0 .1 molar and volume of naoh needed for complete reaction is so it is how much 72 .4 mole sorry 4 ml okay now so here another one thing is given so it has only one acidic hydrogen that reacts with any so that means what one more, so the reaction is 1 is to 1 mole.
01:55
So here if you take cellic acid, it has only one replaceable hydrogen atom.
02:01
Okay.
02:02
So this will react with one mole of an aoh giving the product.
02:07
Okay, so we don't know the product because we don't know the molecular formula of cellic acid.
02:12
So here one thing we know this, we know that the 1 mole of cellic acid is reacting with 1 mole of an aoh because an aoh is acting as a molecule of aoh.
02:20
As a base and it will replace the acidic hydrogen present in the silica.
02:25
Since only one hydrogen is there, it will, one mole of anoach will replace one mole of this particular acidic hydrogen, right? now, first let me find out number of mole of any which present in the reaction.
02:39
So, therefore, number of moles of naoh is equal to, so we have given the molarity, which is 0 .1 molar and volume is 72 .4.
02:53
Ml to convert into liter it is 10 to minus 3.
02:57
So number of moles is 0 .007 to 4.
03:01
Okay so from the equation 1 mol of cellic acid reacts with 1 molar of n .a .o .h.
03:19
Now we have how much 0 .007 to 4 molar of n .a .o .h so this will be neutralized by how much 0 .007 to 4 molar n .a .o .h.
03:29
So this will be neutralized by how much 0 .00 so since it is the exact 1 -1 ratio, so this much mole of cellic acid only used...