Sample of air at conditions 35 c dbt and 60 rh the pressure...

Sample of air at conditions 35 c DBT and 60% RH. The pressure of the air is 1.033 bar. Determine a- vapour pressure and humidity ratio in the air. b- If 5 grams of water vapour is removed from the air and temperature is reduced to 25 c Find the relative humidity and Dew point temperature of the air.

Transcript

00:01 Hello students, in this question a sample of moist air has a dry bulb temperature t of 25 degrees celsius and the relative humidity relative humidity is 50 percent and the barometric pressure of 740 millimeter of hg.

00:27 So for the first part of the question we have to calculate the partial pressure of water vapor and dry air.

00:34 So the partial pressure partial pressure we denoted as pv.

00:45 This is what we have to calculate.

00:48 We know that relative we know that the relative humidity relative humidity pi is equal to pv by ps.

01:07 So here from the steam table we can find the saturation pressure.

01:12 So the saturation pressure ps is equal to 3169 .8 newton per meter square.

01:22 So let's calculate the pv.

01:28 Here the relative humidity that is pi is 50 percentage.

01:32 So it is 0 .5.

01:35 So 0 .5 is equal to pv by 3169 .8.

01:41 This gives the partial pressure pv is equal to 1584 .9 newton per meter square.

01:49 This is the answer for first part of the question.

01:55 Next is we have to find the dew point temperature.

01:57 Since dew point temperature is the saturation temperature corresponding to the partial pressure of water vapor pv.

02:04 So from the steam table we can find the corresponding to a pressure of 1589 .4 newton per meter square.

02:14 So the dew point temperature can be calculated by tdp minus 10 divided by pv that is 1 .5849 minus 1 .2281 is equal to 15 minus 10 divided by 1 .7057 minus 1 .2281...

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