There was an error accessing the educators page.
For the scheme shown in Fig. (R1=8 Ohms, R2=4 Ohms) the current that flows through the resistor R2:
Added by Gdfgdfg S.
Close
Step 1
First, we need to find the total resistance in the circuit. Since the resistors R1 and R2 are connected in series, we can simply add their resistances to find the total resistance: R_total = R1 + R2 = 8 Ohms + 4 Ohms = 12 Ohms Show more…
Show all steps
Your feedback will help us improve your experience
Ashwin Banarsee and 60 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In the circuit below resistors R1 and R2 are in series and have resistances of 5 0 and 10 0, respectively The voltage across resistor R1 is equal to 4 V. Find the current passing through resistor R2 and the voltage across the same resistor:
Shaiju T.
Sri K.
Ohm's law states that for a resistor, the resistance value is equal to the amount of voltage across the resistor divided by the current through the resistor (R = V/I). The units are Ohms (for R), volts (for V), and amperes (for I). R = (8 V)/(4 mA) = ___ kOhms (kiloOhms)
Madhur L.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD