00:03
Okay, we are given this problem where we have a point on the function f of x.
00:07
We want to find another point on this other function y equals 2 times f of x plus 1 plus 6.
00:14
So when they tell us that this point 3, 4 is on the graph f of x, what that is saying is f of negative 3 equals 4.
00:25
The input is our first number in the point.
00:27
That's like our x.
00:28
The output is like our y.
00:30
It's that 4.
00:31
But we just have to be really careful when we're using x and y because we'll see x's and y's down here and those belong to a different function, not the same function.
00:39
So that's why we like this function notation f of x better.
00:44
This is kind of helpful to us because we have this f of negative 3.
00:49
And so if we see an f of negative 3 somewhere, we can replace it with the 4 because we know they're equal to each other.
00:56
So we're gonna pop down here to our second function.
00:59
This is where i see some sort of function notation in this equation.
01:04
I see f of x plus 1.
01:06
So i can't just say that this is f of negative 3 because there's stuff going on in there.
01:14
To figure out the point that we are trying to find for this function, we're looking for some other point x comma y.
01:20
And we can't say x equals negative 3 because if we plug that negative 3 in here, negative 3 plus 1 equals negative 2, which is not anything that we have.
01:30
We don't know what f of 2 is.
01:31
We only know what f of 3 is.
01:34
So instead we want to think about how can we make this f of negative 3? what x value would make this inside right here negative 3? the inside right now is x plus 1...