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Score on last try: 2 of 3 pts. See Details for more. Get a similar question You can retry this question below Given functions $f(x) = \frac{1}{\sqrt{x}}$ and $g(x) = x^2 - 4$, state the domains of the following functions using interval notation. Domain of $\frac{f(x)}{g(x)}$: $(0,2) \cup (2,\infty)$ Domain of $f(g(x))$: $(-\infty,-2) \cup (2,\infty)$ Domain of $g(f(x))$: $(-\infty,0) \cup (0,\infty)$

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Given functions $f(x) = \frac{1}{\sqrt{x}}$ and $g(x) = x^2 - 4$, state the domains of the following
functions using interval notation.
Domain of $\frac{f(x)}{g(x)}$: $(0,2) \cup (2,\infty)$
Domain of $f(g(x))$: $(-\infty,-2) \cup (2,\infty)$
Domain of $g(f(x))$: $(-\infty,0) \cup (0,\infty)$

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Given functions f(x) = (1)/(√(x)) and g(x) = x^2 - 4, state the domains of the following
functions using interval notation.
Domain of (f(x))/(g(x)): (0,2) ∪ (2,∞)
Domain of f(g(x)): (-∞,-2) ∪ (2,∞)
Domain of g(f(x)): (-∞,0) ∪ (0,∞)

Added by Anthony G.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Darshan Maheshwari

01/03/2022

Step 1

Step 1: The domain of $f(x) = \frac{1}{\sqrt{x}}$ is $x > 0$ because the square root of a negative number is undefined and the denominator cannot be zero. Show more…

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Score on last try: 2 of 3 pts. See Details for more. Get a similar question You can retry this question below Given functions $f(x) = \frac{1}{\sqrt{x}}$ and $g(x) = x^2 - 4$, state the domains of the following functions using interval notation. Domain of $\frac{f(x)}{g(x)}$: (0,2) U (2,∞) Domain of $f(g(x))$: (-∞,-2) U (2,∞) Domain of $g(f(x))$: (-∞,0) U (0,∞) Question Help: Video