00:01
There is given a normal distribution.
00:02
So the population mean denoted by mu, that was given as 140 .2, and the population standard deviation which was given as 61 .6 here.
00:11
So we can define a random variable x, this is normally distributed, so the mean and the standard deviation.
00:18
So the samples are given here which is 230.
00:23
So we're going to find the probabilities for the first one.
00:28
So if you just select just one single randomness selected from this population, we have to use the random variable x, and we have to find the probability which is x is greater than 143 .4.
00:41
To get this probability, i'm going to use a graph in this way, calculate your application normal cdf, lower boundary 143 .4, no upper boundary, put for a big number, and the mean is 140 .2, and the standard deviation 61 .6.
00:54
Let's get this value, press second variance, the normal cdf, lower boundary 143 .4, and the upper boundary 1, this is second 899, and the mean is 140 .2, and the standard deviation 61 .6.
01:07
So the probability would be with how many decimal places, four decimal places, which is 4793...