Scores on the Wechsler intelligence quotient (IQ) test for adults have normal probability distribution with a mean score of 100 and a standard deviation of 15 points. The US military has a minimum enlistment standard deviation of 15 points. The Us military has minimum enlistment standards at about an IQ score of 85. Based on IQ scores only, what is probability that a randomly selected adult does not meet Us military enlistment standards?
Added by Joseph P.
Step 1
The z-score is calculated as (X - μ) / σ, where X is the value we're interested in, μ is the mean, and σ is the standard deviation. So, for an IQ of 85, the z-score would be (85 - 100) / 15 = -1. Show more…
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