Question

Laser Wavelength ? Screen (1)+(2) 45° rotated polarizer Mirror 2 (M2) (2) Beam Splitter (BS) L1 (1) H polarizer Mirror 1 (M1) Suppose a photon travels through an interferometer with 2(L2 - L1) = 83 nm. In arm 1, we place a horizontal polarizer, while in arm 2 we place a polarizer at 45 degrees. The wavelength of the laser is 500 nm. Keep in mind: • After traveling through a 45 degree polarizer, the photon will be represented by the wave function $\frac{1}{\sqrt{2}}(\psi_h + \psi_v)$. • After traveling through a horizonal polarizer the photon is represented by the wave function $e^{ikz}\psi_h$. To simplify this problem, we will ask the probability that a photon at the detector is horizontal or vertical. So the probability of observing a photon of any polarization will be normalized to one; that is, P(h) + P(v) = 1. 1) Suppose we block arm 1. What is the probability that a photon we observe at a detector is horizontally polarized? Submit ) Now we open arm 1 so that the sides can interfere. What's the probability that a photon observed at a detector is horizontally polarized? Submit 3) We keep arm 1 open so that the sides can interfere. What's the probability that a photon observed at a detector is vertically polarized? Submit

          Laser
Wavelength
?
Screen
(1)+(2) 45° rotated
polarizer
Mirror 2 (M2)
(2)
Beam Splitter (BS)
L1
(1)
H polarizer
Mirror 1 (M1)
Suppose a photon travels through an interferometer with 2(L2 - L1) = 83 nm. In arm 1, we place a horizontal
polarizer, while in arm 2 we place a polarizer at 45 degrees. The wavelength of the laser is 500 nm. Keep in mind:
• After traveling through a 45 degree polarizer, the photon will be represented by the wave function
$\frac{1}{\sqrt{2}}(\psi_h + \psi_v)$.
• After traveling through a horizonal polarizer the photon is represented by the wave function $e^{ikz}\psi_h$.
To simplify this problem, we will ask the probability that a photon at the detector is horizontal or vertical. So the
probability of observing a photon of any polarization will be normalized to one; that is, P(h) + P(v) = 1.
1) Suppose we block arm 1. What is the probability that a photon we observe at a detector is horizontally polarized?
Submit
) Now we open arm 1 so that the sides can interfere. What's the probability that a photon observed at a detector is
horizontally polarized?
Submit
3) We keep arm 1 open so that the sides can interfere. What's the probability that a photon observed at a detector is
vertically polarized?
Submit

Laser
Wavelength
?
Screen
(1)+(2) 45° rotated
polarizer
Mirror 2 (M2)
(2)
Beam Splitter (BS)
L1
(1)
H polarizer
Mirror 1 (M1)
Suppose a photon travels through an interferometer with 2(L2 - L1) = 83 nm. In arm 1, we place a horizontal
polarizer, while in arm 2 we place a polarizer at 45 degrees. The wavelength of the laser is 500 nm. Keep in mind:
• After traveling through a 45 degree polarizer, the photon will be represented by the wave function
(1)/(√(2))( + ).
• After traveling through a horizonal polarizer the photon is represented by the wave function e^ikz.
To simplify this problem, we will ask the probability that a photon at the detector is horizontal or vertical. So the
probability of observing a photon of any polarization will be normalized to one; that is, P(h) + P(v) = 1.
1) Suppose we block arm 1. What is the probability that a photon we observe at a detector is horizontally polarized?
Submit
) Now we open arm 1 so that the sides can interfere. What's the probability that a photon observed at a detector is
horizontally polarized?
Submit
3) We keep arm 1 open so that the sides can interfere. What's the probability that a photon observed at a detector is
vertically polarized?
Submit

Added by Aitor B.

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