00:01
In this question we have to calculate the coefficient of performance of a heat engine, sorry, or heat pump.
00:08
So, cop of heat pump is equal to the amount of energy delivered or the heat delivered divided by the amount of work it consumes.
00:23
Now, amount of energy delivered can be written as h1 minus h2 divided by w.
00:30
W is the network consumed.
00:34
So now in the question let's suppose this is the vapor dome of r134 gas and this in this manner the gas traveled.
00:57
So here it will be 1 here it will be 2 at 30 % as is given in the question let's call his 3 and 4.
01:06
So now we have to calculate the enthalpy at h1 and h2.
01:15
So according to the question one can write from the data book that h1 is 421 .5 and h2 can be written as 263 .9 plus 0 .3, that is the percent quality into hff.
01:43
That is 421 .5 minus 263 .9.
01:50
Here 263 .9 is the hf that is fluid in thalpe at temperature 45 degrees celsius.
02:00
This is a 45 degrees celsius line.
02:06
So now upon calculation we will get h2 equals to 311 .18.
02:13
Now putting these two values in this equation and the question it has been given work done is the work consume is equals to 1 .5 kilowatt.
02:29
So the net cop will be m.
02:34
Since this h1 and h2 are in per kg term that is a specific enthalpy, so it would be multiplied by m that in mass flow red.
02:45
Into h1 minus h2 divided by total work done or sorry total work consumed so it m is given as 0 .03 into 421 .5 minus 311 .8 whole divided by 1 .5 kilowatt upon solving we will get it is up equals to 2 .2.
03:23
So this is the answer of the question number one or part a...