00:02
Hello students, in the first question in the 24th question we have to find out the force experienced sorry the acceleration on the electron in a electric field.
00:14
So force experienced by the electron will be equal to q into e.
00:18
So force can be written as m a equal to q into e.
00:23
So from this we can find the acceleration so a will be equal to q e divided by m.
00:30
So we can substitute the values.
00:32
So this will be equal to charge of an electron will be 1 .6 into 10 raised to minus 19 and the electric field is given as 600 newton per coulomb divided by mass of the electron will be 9 .1 into 10 raised to minus 31.
00:48
So if we calculate we will get the acceleration a of electron will be equal to 1 .054 into 10 raised to 4 meter per second square.
01:03
So the direction here if electric field is in this direction the force or the acceleration experienced by the electron will be just opposite just opposite to the direction of the electric field.
01:19
Since electric field line starts from positive point and ends at negative point the charge experienced or the force sorry the force or the acceleration experienced by the electron will be just opposite to the direction of electric field.
01:35
So in next question in 25th question we have to find out the force experienced by the electron.
01:44
So force f will be equal to q e.
01:49
So here charge can be taken as 1 .6 into 10 raised to minus 19 and electric field is given as 1360 newton per coulomb.
01:59
So if we calculate we will get the force experienced by the electric field will be equal to 2 .17 into 10 raised to minus 16 newton.
02:10
So this is the magnitude magnitude of the force experienced by the electron.
02:17
So here electric field electric field is in a direction of east.
02:23
So it is directed towards east.
02:26
So the direction of the force will be towards west.
02:30
So the direction of force experienced by the electron will be towards west.
02:35
So in next question in next question we have to find out the electric field experienced by the proton so that will be equal to f by q.
02:47
So here force is given as 2 .75 into 10 raised to minus 14 divided by 1 .6 into 10 raised to minus 19...