5. Use pumping lemma to show that the following language is not context-free: \{b$^m$a$^n$b$^m$ | n>m>0\}. Provide detailed proof.
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Step 2: According to the pumping lemma for context-free languages, there exists a constant p (the pumping length) such that any string s in L with length at least p can be divided into five parts: s = uvwxy, satisfying the following conditions: Show more…
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Sri K.
Using the Pumping Lemma, show why the following language cannot be a regular language: L = {x ∈ {0,1}* | ∃i ∈ I : x = 10^i10^i1 ∧ i > 0} Example: 10101, 1001001, 100010001, etc.
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