00:01
I in this question we have the length of the antenna l is equal to 0 .02 lambda which is less than lambda by 25 then this is equal to so l is equal to dl which is equal to l effective so that is 0 .02 lambda.
00:21
Then we have the radiation range is equal to so radiation range is 60 meters and in the first case we have to find the electric field at so electric field at theta is equal to 90 degree so we have the value of theta as 120 pi.
00:42
Then e as a function of r theta phi comma k it is given by i naught by 2 dl by lambda sin theta into eta divided by r into sin omega t e power minus j beta r into a theta.
01:05
So the value of electric field e is given by it is i naught by 2 into dl by lambda into sin of theta is 90 degree divided by value of r is the radiation range which is 60 meters into eta is 120 pi divided or divided divided by 2 lambda by 60.
01:28
So we have so we have the value of electric field is equal to so here dl is so it is i naught value is 3 amperes divided by 2 into 0 .02 lambda divided by lambda into sin 90 is 1 divided by 60 pi 120 pi.
01:51
So we have the electric field intensity at theta is equal to 90 degree is 0 .1884 volt per meter.
02:00
In the second part of the question we have to find the magnetic field intensity so magnetic field intensity we know that e is equal to h into eta which implies h will be equal to e by eta so we have the value substituted as it is 3 by 2 into 0 .02 into lambda by lambda into sin 90 divided by 60.
02:34
So we have the value it is 0 .01 divided by 20 that is equal to so value of h will be 5 into 10 power minus 4 henry per meter.
02:46
So this is the magnetic field intensity...