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Hello everyone.
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Let's start the question.
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In this question we are given with a sample of a compound for which we have the molar mass of the compound given as 34 grams per mole.
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Also we are given with the mass of the elements present in that compound.
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One is hydrogen which has the mass as 0 .44 grams and oxygen which has 6 .92 grams present.
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We need to determine the molecule of formula for this compound.
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So in order to determine the molecular formula, first we need to calculate the percentage composition of the different elements present.
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So from this, if we see, we can determine the total mass of the elements present in the sample, which would be equal to mass of hydrogen, that is 0 .44 grams, added to the mass of oxygen, which is 6 .92 grams.
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If we carry out the addition, it will be equal to 7 .36 grams.
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Now from this we will be determining the percentage composition of the element.
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Now starting from the percentage composition of the element hydrogen, it will be equal to the given mass that is 0 .44 grams divided by the total mass of element which is 7 .36, multiplied by 100 percentage.
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If we carry out this simplification, it will be equal to 5 .97 percentage.
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So this is the percentage composition that we have obtained for hydrogen.
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Now let's move further and determine the percentage composition of the element oxygen.
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This again would be equal to its given mark.
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Which is 6 .92 grams divided by the total mass which is 7 .36 multiplied by 100 percentage.
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If we carry out the further simplification, it will be equal to 94 .03 percentage.
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In this manner we have determined the percentage composition of both the elements present.
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Now we have the percentage composition.
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We will be determining the empirical formula.
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So for empirical formula for determining the empirical formula of the sample given, we need to make a table by specifying few important things.
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On the left side we will specify the element which are present.
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Then elements, we have two elements.
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One is hydrogen and the other element is oxygen...