Question

Assuming that the function below is defined properly: def func(number1=8, number2=9, number3=10): if number1 > 8: print("the first") elif number2 > number1 / 2: print("the second") else: print("the third") What will be the output of the following function call: func(10,5) Your answer: ? the first ? the second ? the third ? error

          Assuming that the function below is defined properly:
def func(number1=8, number2=9, number3=10):
    if number1 > 8:
        print("the first")
    elif number2 > number1 / 2:
        print("the second")
    else:
        print("the third")

What will be the output of the following function call:
func(10,5)
Your answer:
? the first
? the second
? the third
? error

Assuming that the function below is defined properly:
def func(number1=8, number2=9, number3=10):
if number1 > 8:
print("the first")
elif number2 > number1 / 2:
print("the second")
else:
print("the third")

What will be the output of the following function call:
func(10,5)
Your answer:
? the first
? the second
? the third
? error

Added by Michael L.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Supreeta N

06/23/2023

Step 1

Step 1: The function call func(10,5) will pass 10 as number1 and 5 as number2, while number3 will remain the default value of 10. Show more…

Show all steps

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SEN1011 (1-3 & 901-906)... Overview Plans Resources Follow-up and reports Participants More Question 6 Assuming that the function below is defined properly: def func(number1=8, number2=9, number3=10): if number1 == 8: print("the first") elif number2 == number1/2: print("the second") else: print("the third") What will be the output of the following function call: func(10,5)