Question

A series RL circuit with inductance 6.0 mH and resistance 20 ? is connected to a 12.0-V battery of negligible internal resistance. The current in the circuit 4.0 ?s after the switch is closed is 1.0 mA. 4.0 mA. 7.9 mA. 0.40 A. 0.59 A.

          A series RL circuit with inductance 6.0 mH and resistance 20 ? is connected to a 12.0-V battery of negligible internal resistance. The current in the circuit 4.0 ?s after the switch is closed is
1.0 mA.
4.0 mA.
7.9 mA.
0.40 A.
0.59 A.

A series RL circuit with inductance 6.0 mH and resistance 20 ? is connected to a 12.0-V battery of negligible internal resistance. The current in the circuit 4.0 ?s after the switch is closed is
1.0 mA.
4.0 mA.
7.9 mA.
0.40 A.
0.59 A.

Added by Melissa R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

03/05/2023

Step 1

Step 1: Use the formula for the current in a series RL circuit: \(I(t) = \frac{V}{R} \times (1 - e^{-\frac{Rt}{L}})\), where \(I(t)\) is the current at time \(t\), \(V\) is the voltage of the battery, \(R\) is the resistance, \(t\) is the time, and \(L\) is the Show more…

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Series RL circuit with inductance 6.0 mH and resistance 20 ̐ is connected to a 12.0-V battery of negligible internal resistance. The current in the circuit 4.0 ̐s after the switch is closed is 1.0 mA.