Question

Force(x) 0.45 0.4 0.35 0.3 0.25 0.2 0.15 0.1 .05 0 -0.05 -0.1 -0.15 -0.2 -0.25 -0.3 -0.35 -0.4 -0.45 5.6166666666665388888915989696595959876666663473699999198.99999666666639950000903066629666666388.366666666733-000149 Time

          Force(x)
0.45
0.4
0.35
0.3
0.25
0.2
0.15
0.1
.05
0
-0.05
-0.1
-0.15
-0.2
-0.25
-0.3
-0.35
-0.4
-0.45
5.6166666666665388888915989696595959876666663473699999198.99999666666639950000903066629666666388.366666666733-000149
Time

Added by Lori V.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Dave Kratz

Step 1

- Add a simple pendulum to the workspace. - Set the mass of the bob and the length of the string to match the values used in your physical experiment. Show more…

Show all steps

Thanks for your feedback!

Set up a simple pendulum in Simphy. Get general instructions here. Run the simulation and get data in order to answer the following questions. Make sure you use the same bob’s mass and string’s length as your physical experiment in the next question Q1a) Plot the tension vs. time (careful, Simphy calculates and see THEORY) Q1b) Show that the maximum linear speed and maximum tension agree with eq. 1 Q1c) Also using eq. 1 plot the tension vs. angle of the pendulum Q1d) Based on you data find the maximum displacement angleEquation 1: F r=mar =T-mgcos () (ar=u2r) Do for both graphs pleaseeeeThis are the graphs I got from Symphy 0.45 0.4 0.35 0.3 0.25 0.2 0.15 0.1 .05 0 Fo -0.05 0.1 0.15 -0.2 -0.25 0.3 0.35 -0.4 -0.45 5.6166666634999 33800000014