Seven digit numbers are formed using digits \( 1,2,3,4,5,6,7,8 \), 9 without repetition. The probability of selecting a number such that product of any 5 consecutive digits is divisible by either 5 or 7 is \( P \). Then \( 12 P \) is equal to
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This is given by the permutation of 9 digits taken 7 at a time: \[ 9P7 = \frac{9!}{(9-7)!} = \frac{9!}{2!} = 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 = 181440 \] Show more…
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