00:01
In the given question, a reaction is given as aloh whole thrice react with hcl and the reaction gives alcl3 plus h2o.
00:18
The mass of aloh thrice is given 12 .1 gram and the mass of hcl is given 8 .4 gram.
00:28
We have to find the mass of alcl3 produced.
00:32
So first of all we will write the balance reaction in which the number of atom are equal on the reactant as well as on the product side.
00:39
So the balance reaction for this reaction will be al -o -h -w -w -rise will react with 3h -cl and this gives al -cl plus 3 water molecule.
00:59
Now we will find the mall of each reactant by using the formula, mole is equal to mass divided by molar mass.
01:10
So we will first find the mole of aloh whole thrice.
01:18
This is equal to 12 .1 gram divided by the molar mass that is 78 gram per mole.
01:25
When we solve the calculation, this is equal to 0 .15.
01:29
Now we will find the mole of hcl.
01:35
This is equal to 8 .4 gram divided by the molar mass of hcl that is 36 .5 gram per mole...