00:01
So this question, they've given us two problems.
00:04
Problem a and problem b.
00:07
And they've asked us to find the area of the shaded region and the area of the unshaded region.
00:12
So in this case the area of the shaded region in the first case is basically the one that i'm trying to shade in green.
00:20
Considering that the diameter is given to be 6 and the length is also the same in this case, the area of the circle for the first case is pi r squared.
00:40
So the diameter, so that implies that the radius is equal to 3.
00:49
So pi r squared would mean pi times 3 squared which would be pi and so 9 pi centimeter squared.
00:58
So this is the shaded area, the circle area, the shaded area, shaded circle area.
01:09
The unshaded white region is nothing but the area of the square minus the circle area.
01:29
So area of square is obviously the length squared which means it's 6 squared minus the circle's area is nothing but the 9 pi centimeter squared in both in these cases.
01:46
So 6 squared is 36 minus 9 pi.
01:50
So that is the unshaded region.
01:55
So the unshaded region is 36 minus 9 pi centimeter squared in the first case.
02:00
Similarly in the second case we have two of these regions...