00:01
Hello students, here in the question we have to rank the bulbs according to the brightness.
00:06
So the brightness of the bulb it can be calculated with the power using the formula p equals to i square r where p is the power, i is the current and r is the resistance.
00:17
We are given that all the bulbs are identical and they have same resistance and will have same brightness if the current is passing through them.
00:25
So since the bulbs are identical and connected in series, the current i through each bulb will be same.
00:36
However, voltage v will change and power dissipated depends upon the voltage and the resistance.
00:49
In series circuit for n bulbs in series, we have r total equals to n into r of bulb.
01:05
Since the battery is idle, so v total across the n.
01:14
So calculating the power, we have p equals to i square r for the bulb.
01:24
Since the current is same for all the bulbs, the power dissipated is directly proportional to resistance.
01:33
That is power will be directly proportional to r for the bulb...