Question

Practice Problem 2 For the below given curve in space, find T (unit tangent vector) and k (curvature) r(t) = (\cos t + t \sin t)\mathbf{i} + (\sin t - t \cos t)\mathbf{j} + 3\mathbf{k} What is the value of k (curvature) if t = 2\pi

          Practice Problem 2
For the below given curve in space, find
T (unit tangent vector)
and
k (curvature)
r(t) = (\cos t + t \sin t)\mathbf{i} + (\sin t - t \cos t)\mathbf{j} + 3\mathbf{k}
What is the value of k (curvature) if t = 2\pi

Practice Problem 2
For the below given curve in space, find
T (unit tangent vector)
and
k (curvature)
r(t) = (cost + t sint)𝐢 + (sint - t cost)𝐣 + 3𝐤
What is the value of k (curvature) if t = 2π

Added by Wendy Y.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ashwin Banarsee

Step 1

r(t) = cos(t) + t*sin(t) - t*cos(t)j + 3k v(t) = -sin(t) + sin(t) + t*cos(t) - t*sin(t)j + 0k v(t) = (t*cos(t) - sin(t))i + (t*sin(t) - t*cos(t))j + 0k v(t) = t*cos(t) - sin(t)i + t*sin(t) - t*cos(t)j Show more…

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Practice Problem 2 For the below given curve in space, find T (unit tangent vector) and k (curvature) r(t) = cos(t) + t*sin(t) - t*cos(t)j + 3k What is the value of k (curvature) if t = 2n