Show all your work, including proper units, and correct...

Show all your work, including proper units, and correct significant digits! You must answer the following THREE questions. 1. Phosgene, ( mathrm{COCl}_{2}(mathrm{~g}) ) is an extremely toxic gas. It was used during World War 1. Today it is used to manufacture pesticides, pharmaceuticals, dyes, and polymers. It is prepared by mixing carbon monoxide and chlorine gas. [ mathrm{CO}(mathrm{g})+mathrm{Cl}_{2}(mathrm{~g}) ightleftharpoons mathrm{COCl}_{2}(mathrm{~g}) ] ( 0.055 mathrm{~mol} ) of ( mathrm{CO} ) and ( 0.072 mathrm{~mol} ) of ( mathrm{Cl}_{2} ) are placed in a ( 5.0 mathrm{~L} ) container. At ( 870 mathrm{~K} ), the equilibrium constant is 0.20. What are the equilibrium concentrations of the mixture at ( 870 mathrm{~K} )? KU (6 marks)

Transcript

0:00 Take a look.

00:01 So we're given fosgene formation and this is co and co2.

00:10 So the first order of business i'm going to have is find my concentrations.

00:18 For my co, it will be, i'm going to go 0 .055 moles per 5 .0 liters equals 0 .011 molar.

00:40 And for my cl2 of 0 .072 moles divided by 5 .0 liters, that'll equal 0 .0144 molar.

01:08 0 .144.

01:12 Okay, so now let's do my ice table.

01:16 I'll do this over here.

01:17 So my initial concentration was 0 .10144.

01:41 And 0.

01:50 This is going to decrease by x.

01:53 This will decrease by x.

01:55 This will increase by x.

01:57 This will give me 0 .011 minus x, 0 .0144 minus x, and x.

02:08 My equilibrium expression will be cocl2 over co times cl2.

02:23 So now let's solve.

02:26 This is going to give me 0 .20 equals x over 0 .011 minus minus x times 0 .0144 minus x.

02:47 So let me figure this out now.

02:58 So this will equal x over, this will be plus x squared, 0 .011 times 0 .0144 will be 1 .584 times 10 to the minus 4, minus 0 .011, get these together, minus 0 .0254x plus x squared.

03:38 Okay, let's put these over to the other side.

03:40 So i'll have 0 .20x squared minus 0 .0254 times 0 .2 is 0 .00508x plus 0 .2 times 1 .584 times 10 to the minus.

04:23 Is 3 .168 times 10 to the minus 5th x equals x.

04:33 Now i'm going to have to move everything around here, so i'm going to end up with 0 .80x.

05:05 Okay, so now let me see here.

05:11 I'm going to have x 0 .8x squared squared plus 0 .00508x minus 3 .168 times 10 to the minus fifth.

05:31 I'm underlining that so i can think move that here.

05:35 Okay and then i'm going to go to my apps down to my polyatomic solver.

05:41 I'm going to enter 0 .8.

05:43 Enter.

05:44 Enter.

05:45 0 .00508...

Question

Please give Ace some feedback