Show if n is an integer, then n is odd if and only if 3n-2 is odd. ( 20 points)
Added by Johnny S.
Step 1
Then n = 2k + 1 for some integer k. Compute 3n − 2: 3n − 2 = 3(2k + 1) − 2 = 6k + 3 − 2 = 6k + 1, which is of the form 2(3k) + 1, hence odd. Show more…
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