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ALGORITHM 4 Computing div and mod. procedure division algorithm(a: integer, d: positive integer) q := 0 r := $|a|$ while r ? d r := r - d q := q + 1 if a < 0 and r > 0 then r := d - r q := -(q + 1) return (q, r) {q = a div d is the quotient, r = a mod d is the remainder}

          ALGORITHM 4 Computing div and mod.
procedure division algorithm(a: integer, d: positive integer)
q := 0
r := $|a|$
while r ? d
r := r - d
q := q + 1
if a < 0 and r > 0 then
r := d - r
q := -(q + 1)
return (q, r) {q = a div d is the quotient, r = a mod d is the remainder}
        
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ALGORITHM 4 Computing div and mod.
procedure division algorithm(a: integer, d: positive integer)
q := 0
r := |a|
while r ? d
r := r - d
q := q + 1
if a < 0 and r > 0 then
r := d - r
q := -(q + 1)
return (q, r) q = a div d is the quotient, r = a mod d is the remainder

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Computer Science and Information Technology
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Trishna Knowledge Systems 2018 Edition
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Show that Algorithm 4 uses O(qloga) bit operations, as- suming that a>d. ALGORITHM 4 Computing div and mod. procedure division algorithm( a : integer, d : positive integer) q:=0 r:=|a| while r>=d r:=r-d q:=q+1 if a<0 and r>0 then r:=d-r q:=-(q+1) return is the quotient, r=amodd is the remainder ALGORITHM 4 Computing div and mod. procedure division algorithm(a: integer, d: positive integer) q:=0 1p|=:u while r > d r=r-d q=q+1 if a < 0 and r > 0 then r:=d-r q := -(q+1) return (q, r) {q = a div d is the quotient, r = a mod d is the remainder}
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00:01 Hi, today we are solving the question in which we are given with 3 raise to the power 16 mod 13.
00:09 So if we took this, so firstly converting the exponent to binary form...
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