00:01
So, let's consider a, b belongs to group g.
00:06
Then, assume that the order of a is n.
00:13
We can assume here that first order of a is.
00:22
So, from here this implies that n is is equal to smallest positive integer such that we can write a to the power n is equal to.
00:39
Now, we have to consider here a inverse to the whole power n is equal to a to the power minus of n.
00:52
So, from here we can write a to the power is equal to a to the power n inverse for a positive integer inverse.
01:08
Now, substitute put a to the power n is equal to e.
01:19
So, from here our function will be e to the power minus of one and we know that e to the power minus of one will be e then...