Question

Show that if two thin lenses are close together $(s$, the distance between the lenses, is negligibly small), the two lenses can be replaced by a single equivalent lens with focal length $f_{\mathrm{eq}} .$ Find the value of $f_{\mathrm{eq}}$ in terms of $f_{1}$ and $f_{2}$.

Name: Show that if two thin lenses are close together (s, the distance between the lenses, is negligibly small), the two lenses can be replaced by a single equivalent lens with focal length feq . Find the value of feq in terms of f1 and f2.
Uploaded: 2022-05-23T15:25:53-08:00
Duration: 7 min 58 s
Channel: Vishal Gupta
Description: Show that if two thin lenses are close together (s, the distance between the lenses, is negligibly small), the two lenses can be replaced by a single equivalent lens with focal length feq . Find the value of feq in terms of f1 and f2.

          Show that if two thin lenses are close together $(s$, the distance between the lenses, is negligibly small), the two lenses can be replaced by a single equivalent lens with focal length $f_{\mathrm{eq}} .$ Find the value of $f_{\mathrm{eq}}$ in terms of $f_{1}$ and $f_{2}$.

Added by Timothy H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vishal Gupta

05/23/2022

Step 1

Step 1:** Apply the thin lens equation for the first lens: \[ \frac{1}{C_1I} - \frac{1}{C_1O} = \frac{1}{F_1} \] ** Show more…

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Show that if two thin lenses are close together $(s$, the distance between the lenses, is negligibly small), the two lenses can be replaced by a single equivalent lens with focal length $f_{\mathrm{eq}} .$ Find the value of $f_{\mathrm{eq}}$ in terms of $f_{1}$ and $f_{2}$.