Show that \( \mathbf{v} \) is an eigenvector of \( A \) and find the corresponding eigenvalue, \( \lambda \).
\[
\begin{array}{l}
A=\left[\begin{array}{rrr}
0 & 1 & -1 \\
1 & 1 & 2 \\
1 & 3 & 0
\end{array}\right], \mathbf{v}=\left[\begin{array}{r}
-3 \\
1 \\
1
\end{array}\right] \\
\lambda=\square
\end{array}
\]
Submit Answer
-/8.33 Points]
DETAILS
MY NOTES
POOLELINALG4 4.1.009. O/2 Submissions Used
Show that \( \lambda \) is an eigenvalue of \( A \) and find one eigenvector \( \mathbf{v} \) corresponding to this eigenvalue.
\[
\begin{array}{l}
A=\left[\begin{array}{rr}
0 & 9 \\
-1 & 10
\end{array}\right], \lambda=1 \\
\mathbf{v}=\square \\
\square
\end{array}
\]