Show that frac{1}{n!} - frac{1}{(n+1)!} = frac{1}{(n+1) cdot (n-1)!}
Added by Alison S.
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Step 1
We notice that (n+1)! can be written as (n+1) * n!, so we can rewrite the expression as: n! * (n+1) * n! * (n+1) * (n-1)! Show more…
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