Show that the total energy released in the proton-proton chain is 26.7 MeV, considering the over

Name: Show that the total energy released in the proton-proton chain is 26.7 MeV, considering the overall effect in ^1H+^1H→^2H+e^++ve,^1H+^2H→^3He+γ, and ^3He+^3He→^4He+^1H+^1H . Be sure to include the annihilation energy.
Uploaded: 2021-12-12T05:52:55-08:00
Duration: 3 min 2 s
Channel: Yuva S
Description: Show that the total energy released in the proton-proton chain is 26.7 MeV, considering the overall effect in ^1H+^1H→^2H+e^++ve,^1H+^2H→^3He+γ, and ^3He+^3He→^4He+^1H+^1H . Be sure to include the annihilation energy.

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Vishal Gupta · Accepted Answer

1. In the first step, two protons combine to form a deuterium nucleus, releasing a positron and

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