Question

Calculate the Real (P), Reactive (Q), and Apparent (S) Powers for the circuit below. You are given source V = 120Vrms, resistance of 80 ohms, inductance of 480 mH, capacitance of 110 uF, and frequency of 50 Hz. Calculate the Power Factor. 500 mH WW 10 ohms P = Q = S = Power Factor = circle one: leading or lagging

          Calculate the Real (P), Reactive (Q), and Apparent (S) Powers for the circuit below. You are given source V = 120Vrms, resistance of 80 ohms, inductance of 480 mH, capacitance of 110 uF, and frequency of 50 Hz. Calculate the Power Factor.
500 mH
WW
10 ohms
P =
Q =
S =
Power Factor =
circle one: leading or lagging
        
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show work calculate the realpreactiveqand apparentspowers for the circuit belowyou are given source v120vrms15resistance of 80 ohms inductance of 480 mh capacitance of 110 uf and frequency o 50226

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Calculate the Real (P), Reactive (Q), and Apparent (S) Powers for the circuit below. You are given source V = 120Vrms, resistance of 80 ohms, inductance of 480 mH, capacitance of 110 uF, and frequency of 50 Hz. Calculate the Power Factor. 500 mH WW 10 ohms P = Q = S = Power Factor = circle one: leading or lagging
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Find the average power, the reactive power, and the apparent power supplied by the voltage source in the circuit if vg = 50*cos(10e5*t) V

Adi S.


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Transcript

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00:01 The question that is given over here, this is regarding the resistance and inductance.
00:16 The question is, a 60 hertz 220 v rms source supplies a power to a load consisting of resistance in series with an inductance.
00:27 The real power is 1500 watt and the parent power is 2500 var.
00:34 We have to determine the value of resistance and the value of inductance.
00:38 Group of answer choices are given and we have to select the right answer for this question.
00:43 Over here, we know that the vrms given is 220 volt.
00:48 The frequency f is 60 hertz.
00:51 The real power is 1500 and the parent power is 2500.
00:56 Now the power factor is given by the formula cos pi which is equal to p by s which is 1500 divided by 2500.
01:10 So we get 0 .6.
01:12 The cos pi will be equal to 0 .6...
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