Question

Silver has a density of 1.049 x 10^4 kg/m^3 at 0°C and an average linear expansion coefficient of 1.930 x 10^-5(°C^-1). A 40.00 kg block of silver at 0°C is heated to 85.00°C. (a) What is the density (in kg/m^3) of the silver block at 85.00°C? (Round your answer to at least four significant figures.) kg/m^3 (b) What is the mass (in kg) of the silver block at 85.00°C? kg

          Silver has a density of 1.049 x 10^4 kg/m^3 at 0°C and an average linear expansion coefficient of 1.930 x 10^-5(°C^-1). A 40.00 kg block of silver at 0°C is heated to 85.00°C.

(a) What is the density (in kg/m^3) of the silver block at 85.00°C? (Round your answer to at least four significant figures.)
kg/m^3

(b) What is the mass (in kg) of the silver block at 85.00°C?
kg
        
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Silver has a density of 1.049 x 10^4 kg/m^3 at 0°C and an average linear expansion coefficient of 1.930 x 10^-5(°C^-1). A 40.00 kg block of silver at 0°C is heated to 85.00°C.

(a) What is the density (in kg/m^3) of the silver block at 85.00°C? (Round your answer to at least four significant figures.)
kg/m^3

(b) What is the mass (in kg) of the silver block at 85.00°C?
kg

Added by Shane R.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Silver has a density of 1.049 x 10^3 kg/m^3 at 0°C and an average linear expansion coefficient of 930 x 10^-6 (°C^-1). A 40.00 kg block of silver at 0°C is heated to 85.00°C. What is the density (in kg/m^3) of the silver block at 85.00°C? (Round your answer to at least four significant figures) What is the mass (in kg) of the silver block at 85.00°C?
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Transcript

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00:01 Students in this question we have given that silver has a density of 1 .049 into 10 to the power 4 gram per meter cube at temperature 0 degrees centigrade and average linear expansion coefficient of 1 .930 into 10 to the power minus 5 degrees centigrade inverse mass of 40 kg block is heated to temperature temperature and 85 degrees centigrade.
00:37 For the part a, the density at this temperature we have to calculate...
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