We can use the power of a product rule, which states that $(ab)^n = a^n b^n$.
In this case, $a = 3$, $b = w^3$, and $c = x^{-5}$. So, we have $(3 \cdot w^3 \cdot x^{-5})^2$.
Applying the power of a product rule, we get:
$(3w^3x^{-5})^2 = 3^2 \cdot (w^3)^2 \cdot
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