Step 1:
Use the sine difference identity:
\[
\sin A - \sin B = 2 \cos \left( \frac{A+B}{2} \right) \sin \left( \frac{A-B}{2} \right)
\]
Apply it to \(\sin(9x) - \sin(3x)\):
\[
\sin(9x) - \sin(3x) = 2 \cos \left( \frac{9x + 3x}{2} \right) \sin \left(
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