Simplify \( \left.27^{\frac{1}{4}} \times 3^{\frac{1}{4}} \times(\sqrt[3]{3})^{-4}\right) \) and leave the answer in inder form
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- \(27 = 3^3\), so \(27^{\frac{1}{4}} = (3^3)^{\frac{1}{4}} = 3^{\frac{3}{4}}\). - \(3^{\frac{1}{4}}\) is already in terms of base 3. - \(\sqrt[3]{3} = 3^{\frac{1}{3}}\), so \((\sqrt[3]{3})^{-4} = (3^{\frac{1}{3}})^{-4} = 3^{-\frac{4}{3}}\). Show more…
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