Question

Simplify the expression \frac{x^2+3x-4}{3x^2-48} \cdot \frac{x^3-49x}{x^2+6x-7}

Name: Simplify the expression (x^2+3x-4)/(3x^2-48) ·(x^3-49x)/(x^2+6x-7)
Uploaded: 2021-10-28T06:08:07-08:00
Duration: 46 s
Channel: Suman Saurav Thakur
Description: Simplify the expression (x^2+3x-4)/(3x^2-48) ·(x^3-49x)/(x^2+6x-7)

          Simplify the expression \frac{x^2+3x-4}{3x^2-48} \cdot \frac{x^3-49x}{x^2+6x-7}

Added by Ronald W.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Suman Saurav Thakur

10/28/2021

Step 1

The expression can be factored as: (x^(2)+3x-4) = (x+4)(x-1) (3x^(2)-48) = 3(x^(2)-16) = 3(x+4)(x-4) (x^(3)-49x) = x(x^(2)-49) = x(x+7)(x-7) (x^(2)+6x-7) = (x+7)(x-1) Show more…

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