Question

Simplify the following expression for the given value of x. Assume the angle \theta is acute.\\ $\sqrt{x^2 - 16}$ if $x = -4 \csc \theta$\\ For $x = -4 \csc \theta$, $\sqrt{x^2 - 16} = \boxed{}$ .\\ (Type an exact answer in simplified form.)

          Simplify the following expression for the given value of x. Assume the angle \theta is acute.\\
$\sqrt{x^2 - 16}$ if $x = -4 \csc \theta$\\
For $x = -4 \csc \theta$, $\sqrt{x^2 - 16} = \boxed{}$ .\\
(Type an exact answer in simplified form.)

Simplify the following expression for the given value of x. Assume the angle θis acute.

√(x^2 - 16) if x = -4 cscθ

For x = -4 cscθ, √(x^2 - 16) = .

(Type an exact answer in simplified form.)

Added by Angela S.

Precalculus with Limits

Ron Larson 2nd Edition

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