First, we can factor out the common term from the numerator. Both $15t^2$ and $-t$ have $t$ as a common factor.
$$ 15t^2 - t = t(15t - 1) $$
Now, substitute this back into the expression:
$$ \frac{t(15t - 1)}{3t} $$
Next, we can cancel out the common factor $t$
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